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Applying Pythagoras
Rung 1 of 4 · Discover

Finding the Hypotenuse

You already know a² + b² = c² is true. The first thing it lets you do is find the longest side of a right triangle — the hypotenuse — from the two short ones.

NESA MA4-PYT-C-01Builds on the theorem

PlayDrag the two legs. Watch the hypotenuse update, then hit “show the squares” to see why it works.
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The theorem says the square on the longest side equals the two smaller squares added together: a² + b² = c². Reading it left to right is the whole trick — if you know the two short sides (the legs), you can build the long one (the hypotenuse).

Add the Squares, Then Undo the Square

Say the legs are 6 and 4. Their squares are 36 and 16, and added together that's 52 — so c² = 52. But we want c, not , so we do the opposite of squaring: a square root. c = √52 ≈ 7.2. In the toy, drag the legs and you'll see that the slanted side is always exactly the square root of the other two squares added up.

Say it plainly: to find the hypotenuse, square both legs, add them, then square-root. That last root is just undoing the square so you get a length back, not an area.

Why the Square Root Has to Be There

The theorem is about areas — the actual squares sitting on each side. So a² + b² gives you the area of the big square, which is . A length isn't an area, though, so to turn that area back into the side length you take its square root. Press “show the squares” and you'll literally see the green square on the hypotenuse matching the brass and mustard ones combined.

So Defining It and Using It Are Different Jobs

Last concept you proved the relationship is true. Here you're running it as a tool: known legs in, hypotenuse out. Once that feels automatic, the very next rung adds the second case — finding a shorter side — which is the same idea run slightly differently.

Us, Thinking Out Loud

Why do we square-root at the end instead of stopping at c²?

Where on the triangle is the hypotenuse, every single time?