Leo+DadMade for Leo
Perimeter of Quadrilaterals & Composite Figures
Rung 4 of 4 · Mastery

Perimeter in the Real World

Fencing a yard, framing a picture, edging a garden bed — all perimeter. And sometimes you're handed the total and have to work a side out backwards. This is where it pays off.


BuildDrag the yard to resize it and watch the fencing change. Then try the “reverse challenge”.
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Audio WalkthroughComing Soon
Video ExplainerComing Soon

Anytime you need something that goes around the edge — fencing a yard, the timber to frame a picture, the trim round a garden bed — you're buying a perimeter. Get it wrong and you're either short or wasting money, so this is the bit that really matters.

Fencing a Yard

To fence a rectangular yard you need enough fencing for the whole way round. A yard 9 m long and 5 m wide needs 2 × (9 + 5) = 28 metres of fence. Drag the yard in the toy and the fence length updates live — same shortcut as rung 2, just with metres on the end.

The move: for anything that runs around the edge — fence, frame, ribbon, skirting — you want the perimeter, in plain metres or centimetres. Not the area.

Working Backwards

Often life hands you the total and asks for a missing side. "You've got 28 m of fencing and the yard is 9 m long — how wide can it be?" Start from Perimeter = 2 × (length + width). Undo the doubling first: 28 ÷ 2 = 14, which is one length plus one width. Then take off the length you know: 14 − 9 = 5 m wide. Flip on the reverse challenge in the toy to feel this — you drag a side until the fencing fits exactly.

Why This Is the Finish Line

Adding the sides was the "aha". The rectangle shortcut made it quick. Spotting the missing sides and the fake line on an L-shape made it safe. But buying the right fence, or running the formula backwards to find a missing length — that's the bit that shows up the day you actually build something, or sit the exam. That's mastery.

Us, Thinking Out Loud

What's something at home we'd measure the perimeter of, and why?

The backwards one — how do we "undo" the 2 × (…) to find a side?

Of the four steps, which should we re-drag in a fortnight?